Question

A car takes 12 s to go from v=0m/s to v = 20 m/s at constant acceleration. Part A If you wish to find the distance traveled using the equation d=1/2at2, what value should you use for a?

Answer 1

Answer:

a = 1.67 m/s²

Explanation:

Given that,

Initial speed, u = 0

Final speed, v = 20 m/s

Time, t = 12 s

We need to find the distance traveled using the equation, d = 1/2 at².

Where

a is acceleration, a = (v-u)/t,

$a=\dfrac{20-0}{12}=1.67\ m/s^2$

So,

$d=\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\d=\dfrac{1}{2}\times {v-u}\times t\\\\d=\dfrac{1}{2}\times {20-0}\times 12\\\\d=10\ m$

Hence, the acceleration is 1.67 m/s² and the distance traveled is 10m.