Question

Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to truthfully report the mass). What is the force constant of the spring in such a scale if it the spring stretches 8.50 cm for a 8.1 kg load

Answer 1

Answer:

k = 933.88 N/m

Explanation:

Given that,

The mass of a load, m = 8.1 kg

The displacement in the spring, x = 8.5 cm

We need to find the force constant of the spring. We know that Hooke's law is given by :

F = -kx

Also,

F = mg (Force due to its weight)

So,

$k=\dfrac{mg}{x}\\\\k=\dfrac{8.1\times 9.8}{0.085}\\\\k=933.88\ N/m$

So, the force constant of the spring is equal to 933.88 N/m.