Answer:
2 moles of NO
Explanation:
Our reaction is:
4NH₃ + 5O₂ → 6H₂O + 4NO
4 moles of ammonia react to 5 moles of oxygen in order to produce 6 moles of water and 4 moles of NO
We need to determine the limiting reactant:
Ratio is 4:5, As 4 moles of ammonia react to 5 moles of oxygen and we have 4 moles, we definetely need 5 moles, but the problem is, we only have 2.5 moles of O₂. Oxygen is the limting reagent.
5 moles of O₂ produce 4 moles of NO, according to stoichiometry
2.5 moles of O₂ may produce (2.5 . 4) / 5 = 2 moles of NO
