Question

35
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.
A medical center observed that about 60% of its morning appointments were with elderly patients. The table shows the results of a
simulation used to represent the scenario. The numbers 0 to 5 represent appointments with elderly patients, and the numbers 6 to 9
represent appointments with other patients.
138 169 286 577 224
766 207 320 343 504
958 497 857 425 881
100 999 321 662 688
137889560972 554
755 580 817 174 639
710 182 116 691 415
409 394 702 890 432
937636 908 372 298
705 483 820 694539
The estimated
The estimated probability that it will take at least four patients to find one who is not an elderly patient is
probability that exactly two of three randomly selected morning appointments are with elderly patients is
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Answer 1

The estimated probability that it will take at least four patients to find one who is not an elderly patient is 0.1504.

How to calculate the probability?

The number of patients = 10

Elderly patients = 60%

Non-elderly patients = 100% - 60% = 40%

The probability that the first four patients are elderly will be:

= [0.6^0 × (0.4)^10] + [0.6 × (-0.6)^9] + [0.6² × (1 - 0.6)^8] + [0.6³ × (1 - 0.6)^7

= 0.000105 + 0.0016 + 0.01062 + 0.0425

= 0.1504

The probability that exactly two of three randomly selected morning appointments are with elderly patients will be:

= 0.6² × (1 - 0.6)¹.

= 0.432

Learn more about probability on:

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