Question

What is the equation of the line that passes through (-1,-4) and (2,5)

A. y+1=3(x+4)
B. y+4=-3(x+1)
C. y+4=3(x+1)
D. y-4=-3(x-1)

Answer 1

Answer:

c) y+4=3(x+1)

Step-by-step explanation:

Answer 2

Answer:

C. $y+4=3(x+1)$

Step-by-step explanation:

Hi there!

What we need to know:

• All the given equations are in point-slope form: $y-y_1=m(x-x_1)$ where m is the slope and the given point is $(x_1,y_1)$

1) Determine the slope of the line

$m=\frac{y_2-y_1}{x_2-x_1}$ where the given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the points (-1,-4) and (2,5)

$=\frac{5-(-4)}{2-(-1)}\\=\frac{5+4}{2+1}\\=\frac{9}{3}\\=3$

Therefore, the slope of the line is 3. Plug this into $y-y_1=m(x-x_1)$ :

$y-y_1=3(x-x_1)$

2) Plug the point (-1,-4) into $y-y_1=3(x-x_1)$

$y-(-4)=3(x-(-1))\\y+4=3(x+1)$

Therefore, the correct answer is C.

I hope this helps!