Question

The picture below shows a box sliding down a ramp:

A right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 68 degrees. The length of A

What is the distance, in feet, that the box has to travel to move from point A to point C? (5 points)

14 sin 68°
14 cosec 68°
14 divided by sec 68 degrees
14 divided by cot 68 degrees

Answer 1

The distance that the box has to travel to move from point A to C is 14cosec68°  feet option second is correct.

What is a right-angle triangle?

It is defined as a triangle in which one angle is 90 degrees and the other two angles are acute angles. In a right-angled triangle, the name of the sides are hypotenuse, perpendicular, and base.

We have a right angle triangle(refer to attached picture)

Let's suppose the box has to travel to move from point A to point C is x units

From the right angle triangle:

$\rm sin68 = \frac{14}{x}$

$\rm x = \frac{14}{sin 68}$

We know the opposite sin is cosec

x = 14cosec68°  feet

Thus, the distance that the box has to travel to move from point A to C is 14cosec68°  feet option second is correct.

Learn more about the right angle triangle here:

brainly.com/question/3770177

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