Find the value of the variables please please help me out I will mark you the brainly! Please please

Answer:
[tex]20 = \frac{Far \ arc - Near \ arc}{2}\\\\20 = \frac{160 - (2m +12)}{2}\\\\40 = 160 - (2m + 12)\\2m + 12 = 160 - 40\\2m = 120 -12\\2m = 108\\m = 54[/tex]
Answer:
m = 54
Step-by-step explanation:
The secant- secant angle 20° is half the difference of the intercepted arcs, that is
[tex]\frac{1}{2}[/tex] (160 - 2m - 12) = 20° ( multiply both sides by 2 to clear the fraction )
- 2m + 148 = 40° ( subtract 148 from both sides )
- 2m = - 108 ( divide both sides by - 2 )
m = 54