Answer:
0.97
Explanation:
Let R₁ represent the rate of diffusion of NO.
Let R₂ represent the rate of diffusion of CO.
Molar mass of NO (M₁) = 14 + 16 = 30 g/mol
Molar mass of CO (M₂) = 12 + 16 = 28 g/mol
Thus, the rate of NO to CO can be obtained as follow:
R₁ /R₂ = √(M₂/M₁)
R₁ /R₂ = √(28/30)
R₁ /R₂ = √(28/30)
R₁ /R₂ = 0.97
R₁ : R₂ = 0.97
NO : CO = 0.97
Therefore, the rate of diffusion of NO to CO is 0.97
