Can some one find the vertex for g(x)8x^2-14x+3 Using decimals if necessary

[tex]x_{v}[/tex]Answer:
The vertex of an up - down facing parabola of the formy = ax" + bx + c is xy =
The parabola params are:
a = 8, b = -14, c =3
[tex]x_{v}=b/2a[/tex]
[tex]x_{v}[/tex]=-(-14)/2·8
simplify
[tex]x_{v}[/tex]=-(-14)/2·8
[tex]x_{v} = 7/8[/tex]
Plug in [tex]x_{v}[/tex]=7/8to find the [tex]y_{v}[/tex] value
[tex]y_{v}[/tex]= -25/8
Therefore the parabola vertex is
(7/8 , -25/8)
If a < 0, then the vertex is a maximum value
If a > 0, then the vertex is a minimum value
a = 8
Minimum(7/8 , -25/8)