Answer:
[tex]Sin~30^o=\frac{LJ}{8\sqrt{2} }[/tex]
[tex]8\sqrt{2} (Sin~30^o)=LJ[/tex]
[tex]LJ=4\sqrt{2}[/tex]
[tex]Sin~45^o=\frac{x}{4\sqrt{2} }[/tex]
[tex]4\sqrt{2}(Sin~45)=x[/tex]
[tex]x=4[/tex] ✓
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hope it helps...
have a great day!!
