Question

please help this is due in like ten minutes.

Answer 1

Answer:

x = $\sqrt{14}$

Step-by-step explanation:

Using Pythagoras' identity in both tight triangles.

First in the small triangle to find the third side ( hypotenuse ) h

h² = 1² + 1² = 1 + 1 = 2 ( take square root of both sides )

h = $\sqrt{2}$

Now use the identity in the larger right triangle

x² + h² = 4²

x² + ($\sqrt{2}$ )² = 16

x² + 2 = 16 ( subtract 2 from both sides )

x² = 14 ( take square root of both sides )

x = $\sqrt{14}$