Question

Please help with this, it's due today!!
No links, no joke answers either, thank you! :)

Answer 1

Answer:

Note:

• Rounded to the nearest tenth  

1)

Tangent = opposite leg / adjacent leg

• 14/x = tan 43°
• x = 14 / tan 43°
• x = 15.0

2)

• cos θ = 6/10
• θ = arccos (0.6)
• θ = 53.1°

3)

x = AC

• sin 58 = x/ 4
• x = 4 sin 58°
• x = 3.4

AC = 3.4

• m∠A = 90° - 58° = 32°

4)

• tan (x) = 7/24 ⇒ adjacent leg = 24 and  opposite leg = 7

Hypotenuse is:

• c = $\sqrt{24^2+7^2} = \sqrt{625} = 25$

cosine = adjacent leg / hypotenuse

• cos(x) = 24/25

5)

• sine = opposite side / hypotenuse

Since B is right angle, hypotenuse is AC and C is opposite to AB

• sin (c) = AB/AC
• sin (c) = 12/15 = 4/5