Answer:
our equation specifies that
32
⋅
g
of dioxygen and
4
⋅
g
of dihydrogen give
36
⋅
g
of water upon reaction, so..........
Explanation:
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
g
)
We started with
5.0
⋅
g
32.00
⋅
g
⋅
m
o
l
−
1
=
0.156
⋅
m
o
l
dioxygen
.
Given excess dihydrogen, this molar quantity thus gives
2
×
0.156
⋅
m
o
l
water.
And thus,
2
×
0.156
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
≅
6
⋅
g
water are evolved. Is this reaction exothermic or endothermic?
