Find the expected value of the winnings
from a game that has the following
payout probability distribution:
10
Payout ($) 0 2 4 6
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]
Round to the nearest hundredth.

Find the expected value of the winnings from a game that has the following payout probability distribution 10 Payout 0 2 4 6 Probability 05 02 015 01 005 Expect class=

Respuesta :

Answer: 2.1

Step-by-step explanation:

The expected value of the winnings from the game is $2.1.

How to determine the expected value?

The payout probability distribution is given as:

Payout ($) 0 2 4 6 10

Probability 0.5 0.2 0.15 0.1 0.05

WE need to find the expected value of the winnings from the game.

The expected value is then calculated as:

E(x) = x P(x)

This gives

E(x) = 0 * 0.5 + 2 * 0.2 + 4 * 0.15 + 6 * 0.1 + 10 * 0.05

E(x) = 0 + 0.4 + 0.60 + 0.6 + 0.5

Evaluate the expression

E(x) = 2.1

Hence, the expected value of the winnings from the game is $2.1.

Read more about expected values at:

brainly.com/question/15858152

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