Answer:
The answer is "between 60 and 96 jobs per day".
Step-by-step explanation:
In this solution, there is a mound-sized and symmetrical distribution for the number of works submitted to your computer per day with mean=78, and standard deviation=6.
Therefore a distribution of 95% decreases between the average [tex]\pm[/tex] 3* standard deviation
Therefore,
[tex]\to 78\pm (3*6)=(78-18, 78+18)=(60,96)[/tex]
The 95% distribution falls in between 60 and 96 jobs per day.