Answer:
The test statistic is [tex]z = 1.25[/tex]
Step-by-step explanation:
We are interested in determining whether or not the proportion of the student who experience anxiety during the exam is significantly more than 80%.
At the null hypothesis, we test if the proportion is 80%, that is:
[tex]H_0: p = 0.8[/tex]
At the alternate hypothesis, we test if the proportion is more than 80%, that is:
[tex]H_a: p > 0.8[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
80% is tested at the null hypothesis:
This means that [tex]\mu = 0.8, \sigma = \sqrt{0.2*0.8} = 0.4[/tex]
A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam.
This means that [tex]n = 100, X = \frac{85}{100} = 0.85[/tex]
The test statistic is
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.85 - 0.8}{\frac{0.4}{\sqrt{10}}}[/tex]
[tex]z = 1.25[/tex]
The test statistic is [tex]z = 1.25[/tex]