Question

Michelle and Pierre both want to buy guitars, Michelle has already saved $60, and
plans to save $5 per week until she can buy the guitar, Pierre has $25, and plans to save
$12 per week. How many weeks will pass before Michelle and Pierre have the same
amount of money?

Answer 1

Answer:

on the 5th week they would both have the same amount of money they would both have a total of 85$

Step-by-step explanation:

Answer 2

The number of weeks will pass before Michelle and Pierre have the same amount of money will be 5.

What is the solution of the equation?

The solution of the equation means the value of the unknown or variable.

Let x be the number of the weeks and y be the total amount.

Michelle and Pierre both want to buy guitars, Michelle has already saved $60, and plans to save $5 per week until she can buy the guitar, Pierre has $25, and plans to save $12 per week.

Then the equations will be

y = 5x + 60    ....1

y = 12x + 25  ....2

Subtract equation 1 from equation 2. Then we have

7x – 35 = 0

       7x = 35

         x = 5 weeks

Then the number of weeks will pass before Michelle and Pierre have the same amount of money will be 5.

More about the solution of the equation link is given below.

https://brainly.com/question/545403

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