Answer:
v = 3.84 m/s
Explanation:
In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:
[tex]Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}[/tex]
where,
v = minimum speed = ?
g = acceleration due to gravity = 9.81 m/s²
r = radius = 10 m
μ = coefficient of friction = 0.15
Therefore,
[tex]v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}[/tex]
v = 3.84 m/s