Question

Use the table to identify the values of pand that should be used to factor x2
+ 3x - 10 as (x + p)(x + 9).
р
1
-1
2.
-2
a
--10
10
-5
5
p+a
-9
9
-3
3
A. -2 and 5
B. -1 and 10
C. 1 and -10
O D. 2 and -5

Answer 1

Answer:

$p =-2$

$q = 5$

Step-by-step explanation:

Given

$(x^2 + 3x - 10) = (x + p)(x + q)$

Required

Find p and q

$(x^2 + 3x - 10) = (x + p)(x + q)$

Open brackets

$x^2 + 3x - 10 = (p + q)x + pq$

By comparison

$(p + q)x = 3x$

$pq = -10$

$(p + q)x = 3x$ implies that:

$p + q = 3$

From the table, the value of p and q that corresponds to $p + q = 3$ is:

$p =-2$

$q = 5$