Answer:
([-3], [0]), ([3], [0])
Step-by-step explanation:
The given equation of the hyperbola is presented as follows;
[tex]\dfrac{x^2}{9} - \dfrac{y^2}{49} = 1[/tex]
The vertices of an hyperbola (of the form) [tex]\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1[/tex] are (± a, 0)
The given hyperbola can we presented in a similar form as follows;
[tex]\dfrac{x^2}{9} - \dfrac{y^2}{49} = \dfrac{x^2}{3^2} - \dfrac{y^2}{7^2} = 1[/tex]
Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;
The vertices of the parabola are ([-3], [0]), ([3], [0]).
