Question

1) A student obtains 0.30 liters of 2.0 M silver nitrate solution. She dilutes
the solution until it has a volume of 2.6 liters. What is the molarity of
the new solution?

Answer 1

Answer: The molarity of the new solution is 0.23 M.

Explanation:

Given: $V_{1}$ = 0.30 L,    $M_{1}$ = 2.0 M

$V_{2}$ = 2.6 L,              $M_{2}$ = ?

Formula used to calculate the molarity of new solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\2.0 M \times 0.30 L = M_{2} \times 2.6 L\\M_{2} = 0.23 M$

Thus, we can conclude that the molarity of the new solution is 0.23 M.