Question

What is the pressure that 0.0100 mol of carbon dioxide gas will exert at a temperature of 46.2oC when it occupies a volume of 5.00 L? I know the answer I just need an explanation of the work.

Answer 1

Answer:

0.052 atm

Explanation:

Assuming the gas will behave as an ideal gas, we can solve this problem by using the PV = nRT equation:

• P = ?

• V = 5.00 L

• n = 0.0100 mol

• R = 0.082 atm·L·mol⁻¹·K⁻¹

• T = 46.2 °C ⇒ 46.2 + 273.2 = 319.4 K

We input the data:

• P * 5.00 L = 0.0100 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 319.4 K

And solve for P:

• P = 0.052 atm