how to find the length of EF?

[tex]CD = \frac{HG + EF}{2} \Leftrightarrow EF = 2CD - HG[/tex]
[tex]2x - 2 = 2x - x + 3\\2x - 2x + x = 3 + 2\\x = 5[/tex]
[tex]EF = 2 * 5 - 2 = 10 - 2 = 8[/tex]
Answer: 8.
Answer:
EF=8
Step-by-step explanation:
HG=x-3
CD=x
EF=2x-2
Since HG is 3 less than CD, EF has to be 3 more than CD
x+3=2x-2
3+2=2x-x
5=x
x=5
HG=2
CD=5
EF=8