Question

Two blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one block with mass m1=14.25 kg is on a horizontal table and the other block with mass m2=7.5 kg hangs vertically. Both blocks experience gravity and the tension force, T. Find the magnitude of the tension in the rope, T, in newtons.

Answer 1

The magnitude of the tension in the rope of this two-block system is:

$T=73.56\: N$

We have here an equilibrium system, which means that all forces acting are equal to zero.

We can analyze the hanging block. We just two forces acting in this block, the tension upwards (T) direction and the weight downward (W) direction.

$T-W_{2}=0$

$T=W_{2}$

$T=m_{2}g$

$T=m_{2}g$

The mass of the second mass is 7.5 kg and g = 9.81 m/s².

$T=7.5*9.81$

$T=73.56\: N$

Therefore, the tension will be 73.56 N.

You can learn more about tension forces here:

https://brainly.com/question/11623464

I hope it helps you!