Question

What is the specific heat capacity of silver metal if 110.00 g of the metal
absorbs 396 J of heat and the temperature rises 15.0°C ?

Answer 1

Answer:

"0.24 J/g.k" is the appropriate solution.

Explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C  

Now,

The specific heat will be:

⇒  $q=ms \Delta T$

On putting the given values, we get

⇒  $396=110.00\times s\times 15.0$

⇒  $396=s\times 1650$

⇒      $s=\frac{396}{1650}$

⇒         $=0.24 \ J/g.k$