Question

Carlos plays college soccer, and will attempt two goals in a row.
A = the event Carlos is successful on his first attempt. P(A) = 0.60.
B = the event Carlos is successful on his second attempt. P(B) = 0.55.
The probability that he makes the second goal GIVEN that he made the first goal is
0.35
What is the probability that he makes both goals?

Answer 1

21%

Since Carlos needs to make both goals, we must multiply the probability that he makes goal 1 with the dependent probability that he makes goal 2 after goal 1. Since we are given these values as 0.60 and 0.35, we multiply them to find a probability of (0.6)(0.35) = 0.21