Question

A sample of seawater contains 78.0 grams of NaCl in 2,025 mL of solution. If the molar mass of NaCl is 58.443 g/mol, what is the molarity of this sample?

0.659 M NaCl
0.823 M NaCl
1.84 M NaCl
2.08 M NaCl

Answer 1

Answer:

0.659 M NaCl

Explanation:

Equation: Molarity = moles of solute / liters of solution

1. To find moles of solute:

78.0 g NaCl x 1 mol NaCl / 58.44 g NaCl

= 1.334 mol NaCl

2. Calculate molarity

Transfer 2,025 mL to L

1.334 / 2.025 = 0.659 M NaCl (rounded)

Answer 2

The molarity of the sample of seawater that contains 78.0 grams of NaCl in 2,025 mL of solution is 0.66M.

How to calculate molarity?

The molarity of a solution can be calculated by dividing the number of moles by its volume.

However, the number of moles of the substance can be calculated as follows:

no of moles = 78g ÷ 58.443g/mol

no of moles = 1.335mol

molarity = no of moles ÷ volume

molarity = 1.335mol ÷ 2.025L

molarity = 0.66M

Therefore, the molarity of the sample of seawater that contains 78.0 grams of NaCl in 2,025 mL of solution is 0.66M.

Learn more about molarity at: https://brainly.com/question/2817451