Answer:
The original fraction is [tex]\frac{2}{5}[/tex]
Step-by-step explanation:
Let the numerator by X
Denominator is three more than its numerator i.e X +3
When both the numerator and denominator are increased by one the fraction becomes 1/2
[tex]\frac{X + 1}{X+3+1} = \frac{1}{2} \\\frac{X+1}{X+4} = \frac{1}{2} \\2X + 2 = X+4\\X = 2[/tex]
Thus, numerator = 2
Denominator = X +3 = 2+3 = 5
The original fraction is [tex]\frac{2}{5}[/tex]