Question

What volume of 2.0M HCl is needed to prepare 0.50L of a 0.75M solution?
Please show your work

Answer 1

Answer:

V = 0.5 L

Explanation:

Given that,

The volume of HCl, V = 2 M

We need to find the volume of 2.0M HCl is needed to prepare 0.50L of a 0.75M solution.

Let n be the number of moles of HCl.

$n=c\times V$

Where

c is molarity

$n=2\times 0.5\\\\n=1\ mol$

Let V be the volume of the solution. So,

$V=\dfrac{n}{c}\\\\V=\dfrac{1}{2}\\\\V=0.5\ L$

So, the required volume of the solution is equal to 0.5 L.