Answer:
5.25 moles.
Explanation:
The decomposition reaction of NaN₃ is as follows :
[tex]2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)[/tex]
We need to find how many grams of N₂ produced in the process.
From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.
2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,
3.5 moles of sodium azide decomposes to give [tex]\dfrac{3}{2}\times 3.5=5.25[/tex] moles of nitrogen gas.
Hence, the number of moles produced is 5.25 moles.
