Respuesta :
Answer:
def move_to_row(num_circle):
x_value = -((num_circle*50)/2)
y_value = -250 +(50*row_value)
penup()
setposition(x_value,y_value)
pendown()
def draw_circle_row(num_circle):
for i in range(num_circle):
endown()
circle(radius)
penup()
forward(diameter)
#### main part
speed(0)
radius = 25
diameter = radius * 2
row_value = 1
num_circle = int(input("How many circle on the bottom row? (8 or less): "))
penup()
for i in range(num_circle):
move_to_row(num_circle)
row_value=row_value+1
draw_circle_row(num_circle)
num_circle=num_circle-1
In this exercise we have to use the knowledge of the python language to write the code, so we have to:
The code is in the attached photo.
So to make it easier the code can be found at:
def move_to_row(num_circle):
x_value = -((num_circle*50)/2)
y_value = -250 +(50*row_value)
penup()
setposition(x_value,y_value)
pendown()
def draw_circle_row(num_circle):
for i in range(num_circle):
endown()
circle(radius)
penup()
forward(diameter)
#### main part
speed(0)
radius = 25
diameter = radius * 2
row_value = 1
num_circle = int(input("How many circle on the bottom row? (8 or less): "))
penup()
for i in range(num_circle):
move_to_row(num_circle)
row_value=row_value+1
draw_circle_row(num_circle)
num_circle=num_circle-1
See more about python at brainly.com/question/26104476
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