Question

The movement of moving particles is described in the equation r=ht22 −2vt−2c. Solve the equation for v.

Pls help

Answer 1

Answer:

$v=\dfrac{r-ht^2+2c}{-2t}$

Step-by-step explanation:

The given equation is :

$r=ht^2 -2vt-2c$

We need to solve the above equation for v.

Subtract ht² from both sides.

r-ht²= ht²-2vt-2c-ht²

r-ht² = -2vt-2c

Adding 2c both sides,

r-ht² +2c= -2vt-2c+2c

r-ht² +2c = -2vt

Dividing both sides by (-2t)

$v=\dfrac{r-ht^2+2c}{-2t}$

So, the value of v is equal to $\dfrac{r-ht^2+2c}{-2t}$.