NO LINKS. Find the segment length indicated. Assume that lines which appear to be tangent are tangent. PLEASE SHOW WORK!!
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Answer:
? = 9.2
Step-by-step explanation:
The angle between a tangent and radius at the point of contact is 90°
Then the triangle shown is right with legs ? , 6.9 and hypotenuse = (6.9 + 4.2) = 11.5
Using Pythagoras' identity in the right triangle
?² + 6.9² = 11.5²
?² + 47.61 = 132.25 ( subtract 47.61 from both sides )
?² = 84.64 ( take the square root of both sides )
? = [tex]\sqrt{84.64}[/tex] = 9.2
Answer:
Solution given:
BC=BD=6.9 units
AD=4.6units
Now
AB=4.6+6.9=11.5units.
we have
<C=90°[the line from the tangent is perpendicular to the radius of circle]
we know that ∆ABC is a right angled triangle.
hypotenuse [h]=AB=11.5units
base[b]=BC=6.9 units
perpendicular [p]=x units
By using Pythagoras law
h²=p² +b²
11.5²=x²+6.9²
x²=11.5²-6.9²
x²=84.64
x=[tex] \sqrt{86.64} [/tex]=9.2
Sothe segment length indicated is 9.2 units.