Question

Select the two values of x that are roots of this equation.
+ 33-3=0
A. x.-345
-3-√21
2
c. x = -3+727
D.
-3- v3
2

Answer 1

Answer:

A and B

${x}^{2} + 3x - 3 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3± \sqrt{21} }{2}$