Question

NaCl+AgNO3–>AgCl+NaNO3

If 45g of salt reacts with sliver nitrate what mass of sliver chloride will be produced?

Answer 1

Answer:

45g of NaCl x 1mole of NaCl/58.5g

= 0.769moles of Nacl

Now Looking at the equation

1mole of Nacl produces 1mole of AgCl

so

0.769mole of NaCl will produces the same Mole of AgCl(0.769)

So the Moles of AgCl produced = 0.769

Recall

Mole = Mass /Molar Mass

Mass = Mole x Molar Mass

Molar Mass of AgCl =108 + 35.5 = 143.5

Mass of Agcl = 0.769 x 143.5

=110.35g of AgCl

Answer 2

Answer:

m = 4.2gAgCl

Explanation:

1. The balanced equation is: 2AgNO,+Ba Cl2–2AgCl+Ba/NO;)