Given:
The area of a sector = [tex]9\pi\text{cm}^2[/tex]
The sector cover [tex]\dfrac{1}{4}[/tex] of the entire circle.
To find:
The radius of the circle.
Solution:
Let r be the radius of the circle. Then, the area of the circle is:
[tex]A=\pi r^2[/tex]
It is given that the sector cover [tex]\dfrac{1}{4}[/tex] of the entire circle. So, the area of the sector is equal to [tex]\dfrac{1}{4}[/tex] of the area of the entire circle.
[tex]9\pi=\dfrac{1}{4}\times \pi r^2[/tex]
Multiply both sides by 4.
[tex]36\pi =\pi r^2[/tex]
Divide both sides by [tex]\pi[/tex].
[tex]36 =r^2[/tex]
Taking square root on both sides.
[tex]\pm \sqrt{36} =r[/tex]
[tex]\pm 6 =r[/tex]
Radius of a circle cannot be negative. So, [tex]r=6[/tex].
Therefore, the radius of the circle is 6 cm.