Question

tanθ=

a. 1 - cot^2 θ
b. 1/cot θ
c. 1 + sec^2 θ

Answer 1

Answer:

$tanθ = \frac{sinθ}{cosθ} \\ = \frac{1}{ \frac{cosθ}{sinθ} } \\ = \frac{1}{cotθ}$

b. 1/cot θ

Answer 2

Answer:

$tanθ = \frac{sinθ}{cosθ} \\ = \frac{1}{ \frac{cosθ}{sinθ} } \\ = \frac{1}{cotθ}$