Respuesta :

msm555

Answer:

Expression on single algorithm

7.

ln 4+ln 3x

ln 4*3x

=ln 12x

8.½ln 256 -3 ln 2

[tex]ln(256) {}^{ \frac{1}{2} } - ln {2}^{3} [/tex]

[tex]ln {16}^{ \frac{2}{2} } - ln8[/tex]

[tex]ln \: \frac{16}{8} [/tex]

ln 2

9.

7 ln a -4 ln b

[tex]ln \: {a}^{7} - ln \: b {}^{4} [/tex]

[tex]ln \: \frac{ {a}^{7} }{ {b}^{4} } [/tex]

Note:

coefficient is a power

and

divide when there is subtract[-]

multiply when there is addition [+]

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