when the profit is 0; then P(t)=0
You have this equation:
t⁴-5t²+4=0
Then, you have to do the following change:
t²=z
you have this other equation:
z²-5t+4=0
Now, you can solve this square equation:
z=[5⁺₋√(25-16)]/2=(5⁺₋√9)/2=
you have two solutions for z.
z₁=(5-3)/2=1
z₂=(5+3)/2=4
Now; if z=1; then
t²=z
t²=1
t=⁺₋√1
We have two solutions:
t=-1 this is not a valid solution:
t=1;
Then in 2001 (2000+t=2000+1=2001) the profit was 0.
If z=4, then:
t²=z
t²=1
t=⁺₋√4
We have two solutions:
t=-2 this is not a valid solution:
t=2;
Then in 2002 (2000+t=2000+2=2002) the profit was 0.
Answer: the yeares in which the profict was 0, were 2001 and 2002.