Respuesta :
basically, we end up with a false statement like
0=3
or something like that
so simplfy each
A.
-5+8x-9=3(x+3)
8x-14=3x+9
minus 3x both sides
5x-14=9
add 15
5x=23
we see we will get a solution
B.
distribute
-12+6x=-12+6x
we can see there are infinite solutions
C.
6-2(3-2x)=-4(3-x)
6-6+4x=-12+4x
0+4x=-12+4x
minus 4x both sides
0=-12
false
here is our answer
C is the one with no solution
0=3
or something like that
so simplfy each
A.
-5+8x-9=3(x+3)
8x-14=3x+9
minus 3x both sides
5x-14=9
add 15
5x=23
we see we will get a solution
B.
distribute
-12+6x=-12+6x
we can see there are infinite solutions
C.
6-2(3-2x)=-4(3-x)
6-6+4x=-12+4x
0+4x=-12+4x
minus 4x both sides
0=-12
false
here is our answer
C is the one with no solution