Question

Given triangle ABC, A = 120°, a = 8, b = 3; determine B to the nearest whole degree.

Answer 1

Sin A / a = Sin B / b Sin 120°/8 = Sin B/3 Cross multiply to get 3 • Sin 120° = 8 • Sin B Sin 120° is (sqrt3 / 2) 3•(sqrt3 / 2) = 8 •sin B 3•sqrt3 / 2 = 8• sin B (3•sqrt3 / 2)/8 = sin B 3•sqrt3 / 2 • 1/8 = sin B 3•sqrt3 / 16 = sin B 0.3247595264 = sin B By using sin inverse we get m