Answer:
19.1 mol H2
Explanation:
1. Hello, first you have to propose the chemical equation:
H2 + CO2 = H2O + CO
The equation has to be balanced, it means that the same quantity of atoms must be in the right and left side of the equation.
2. To do the stochiometric calculus, you need to find which one is the limiting reactant, in the problem says that you are working with an excess of carbon dioxide, so the limiting reactant is hydrogen H2:
Limiting reactant: H2
Excessing reactant : CO2
3. With the limiting reactant and the chemical equation, you have to establish the stichometrical relation to calculate the quantity of all reactants and products:
In a base of the chemical equation, and using the limiting reactant:
1 mol H2 = 1 mol H2O
The exercise says that you have 19.1mol of water vapor (H2O(g)), then to calculate the mol of H2 you need, you make the calculus as follow:
19.1 mol H2O ×( 1mol H2/1 mol H2O)= 19.1 mol H2
The exercise completed is in the document attached.
