multiply both sides by 5 4x^2=10x-4 divide both sides by 2 2x^2=5x-2 minus 5x from both sides and add 2 to both sides 2x^2-5x+2=0 use quadratic formula for ax^2+bx+c=0 x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
given 2x^2-5x+2=0 a=2 b=-5 c=2 x=[tex] \frac{-(-5)+/- \sqrt{(-5)^2-4(2)(2)} }{2(2)} [/tex] x=[tex] \frac{5+/- \sqrt{25-16} }{4} [/tex] x=[tex] \frac{5+/- \sqrt{9} }{4} [/tex] x=[tex] \frac{5+/- 3}{4} [/tex] x=(5+3)/4 or (5-3)/4 x=8/4 or 2/4 x=2 or 1/2