Respuesta :
Answer:
[tex]h(x)=\frac{x}{2}-\frac{1}{2}[/tex]
Step-by-step explanation:
Hello
Step1
Let f(x)=y
f(x) = 2x + 1
(1)y= 2x + 1
to find the inverse of f(x)
Replace every x with a y and replace every y with an x
y= 2x + 1
replacing
x=2y+1
Step 2
Now solve the equation for y
x=2y+1
subtract 1 on both sides
x-1=2y+1-1
x-1=2y
divide boths dies by 2
(x-1)/2=2y/y
[tex]\frac{x-1}{2} =\frac{2y}{2} \\y=\frac{x-1}{2}[/tex]
let this last equation h(x)= inverse of f(x)
[tex]h(x)=\frac{x-1}{2}\\h(x)=\frac{x}{2}-\frac{1}{2}[/tex]
Have a great day