Respuesta :
Answer: x = -1
WORKINGS
We are to solve the cube root equation, ∛x – 1 + 2 = 0
Solve like terms; subtract 1 from 2 to get -1 (-1 + 2 = +1)
Therefore, ∛x + 1 = 0
Move +1 to the right side of the equation, since it does not contain the variable to solve for.
∛x + 1 = 0
Subtract 1 from both sides of the equation
∛x + 1 – 1 = 0 – 1
∛x = -1
Cube both sides of the equation in order to remove the radical on the left side
(∛x)^3 = (-1)^3
x = -1
WORKINGS
We are to solve the cube root equation, ∛x – 1 + 2 = 0
Solve like terms; subtract 1 from 2 to get -1 (-1 + 2 = +1)
Therefore, ∛x + 1 = 0
Move +1 to the right side of the equation, since it does not contain the variable to solve for.
∛x + 1 = 0
Subtract 1 from both sides of the equation
∛x + 1 – 1 = 0 – 1
∛x = -1
Cube both sides of the equation in order to remove the radical on the left side
(∛x)^3 = (-1)^3
x = -1
we have
[tex] \sqrt[3]{x} -1+2=0 [/tex]
Step 1
Solve like terms
[tex] \sqrt[3]{x}+(-1+2)=0 [/tex]
[tex] \sqrt[3]{x}+(1)=0 [/tex]
Step 2
Subtract 1 from both sides of the equation
[tex] \sqrt[3]{x}+1-1=0-1 [/tex]
[tex] \sqrt[3]{x}=-1 [/tex]
Step 3
Cube both sides of the equation in order to remove the radical on the left side
[tex] (\sqrt[3]{x})^{3}=(-1 )^{3} \\ x=-1 [/tex]
therefore
the answer is
[tex] x=-1 [/tex]