Question

solve log2+log16/15+12log25/24+7log8
$log_{10}2+ log_{10} \frac{16}{15} + 12 log_{10} \frac{25}{24} + 7 log_{10} \frac{81}{80 = 1$
1/80=1​

Answer 1

Answer:

the answer is -non existent

Step-by-step explanation:

there is no answer to this problem