Respuesta :
Answer:
We first ALWAYS have to split the figure apart from each other,
lets split it into a triangle and a square!
Let's find the area of the triangle:
20(height) x 20(base) = 400!
400 x 1/2 (just dividing by 2) = 200!
*Remember* Formula of a triangle is:
B(base) x H(height) x 1/2 (basically dividing by 2)
Now time to find the area of the square!
20 x 20 = 400!
Now let's add both their areas:
400 + 200 = 600!
Step-by-step explanation:
600cm2 is your answer.
The figure has an area of 600 square centimeters.
In this question we need to determine the area of the entire figure, this area is the sum of the areas of a square and two symmetric right triangles, defined by respective formulas, that is:
[tex]A = A_{s} + 2\cdot A_{t}[/tex] (1)
Where:
- [tex]A[/tex] - Total area, in square centimeters.
- [tex]A_{s}[/tex] - Square area, in square centimeters.
- [tex]A_{t}[/tex] - Triangle area, in square centimeters.
By applying area formulas for squares and triangles, we expand (1):
[tex]A = x^{2} + \frac{1}{2}\cdot x\cdot y[/tex] (2)
Where:
- [tex]x[/tex] - Side length of the square, in centimeters.
- [tex]y[/tex] - Height of the two right triangles, in centimeters.
If we know that [tex]x = 20\,cm[/tex] and [tex]y = 20\,cm[/tex], then the area of the figure is:
[tex]A = \frac{3}{2}\cdot (20\,cm)^{2}[/tex]
[tex]A = 600\,cm^{2}[/tex]
The figure has an area of 600 square centimeters.
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