Respuesta :

Answer: There are [tex]40.41 \times 10^{23}[/tex] molecules present in 6.71 moles of [tex]NH_{3}[/tex].

Explanation:

Given: Moles of [tex]NH_{3}[/tex] = 6.71 mol

According to the mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{22}[/tex] molecules.

Therefore, molecules present in 6.71 moles are calculated as follows.

[tex]Molecules = moles \times 6.022 \times 10^{23}\\= 6.71 \times 6.022 \times 10^{23}\\= 40.41 \times 10^{23}[/tex]

Thus, we can conclude that there are [tex]40.41 \times 10^{23}[/tex] molecules present in 6.71 moles of [tex]NH_{3}[/tex].