Question

What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1 ? (Radical Expressions)
Discontinuity at (−1, 1), zero at ( four thirds , 0)
Discontinuity at (−1, 1), zero at ( negative four thirds , 0)
Discontinuity at (1, 7), zero at ( four thirds , 0)
Discontinuity at (1, 7), zero at ( negtive four thirds , 0)

Answer 1

Answer:

Discontinuity at (1, 7), zero at (-4/3 , 0)

Step-by-step explanation:

$3x^{2} + x - 4$ = (3x + 4)(x - 1) = 0

                        x = -4/3   or 1

But x = 1 makes f(x) undefined, so there is discontinuity at x = 1

and there is a zero at x = -4/3.

3x + 4 = 3(1) + 4 = 3 + 4 = 7

If you were to graph this function, then you would get the line y = 3x + 4 with a hole at (1, 7).   The line would cross the x-axis at (-4/3, 0) with discontinuity at (1, 7)

Answer 2

The answer is the 1.7. You eject know that because