Question

HELP ASAP PLEASE {will gave thanks and a brainliest}

Answer 1

First lets review property of exponents:
$(a^m)^n = a^{m*n}$
$(\frac{a}{b})^m = \frac{a^m}{b^m}$
$a^m *a^n = a^{m+n}$
$a^{-m} = \frac{1}{a^m}$
$a^0 = 1$

Ok now we can do this problem:
$(2^{8(-2)} * 3^{(-5)(-2)}*1^{-2}) \frac{3^{(-2)(4)}}{2^{3(4)}} * 2^{28}$
$(2^{-16} *3^{10}*1)(\frac{3^{-8}}{2^{12}})*2^{28}$
$(2^{-16 -12+28}) (3^{10 -8})$
$(2^0)(3^2)$
$= 9$